Alfred B Slaybaugh 1922 — 2005

Born on Nov 26, 1922 Alfred B Slaybaugh passed away on Jun 12, 2005, at the age of 82 and was buried in Saybrook Cemetery in Ashtabula, OH. Alfred B Slaybaugh had 1 children: Alan Slaybaugh.

Birth:
Nov 26, 1922
Death:
Jun 12, 2005 (aged 82)
Born in:
Ashtabula, OH
Burial place:
Saybrook Cemetery
Ashtabula, OH
Alfred B Slaybaugh

Passed away Relatives of Alfred B Slaybaugh

children

1950 — 2014 (aged 64)
Birth place:
Ashtabula, OH
Burial place:
Address:
Ashtabula, OH

Who is Else Buried at Saybrook Cemetery in Ohio

1950 — 2014 (aged 64)
Birth place:
Ashtabula, OH
1933 — 1935 (aged 2)
1852 — 1875 (aged 23)
1922 — 2015 (aged 93)
Birth place:
Ashtabula, OH
1879 — 1970 (aged 91)
1831 — 1916 (aged 85)
1900 — 1901 (aged 1)
1904 — 1931 (aged 27)
Birth place:
Geneva, OH
1811 — 1891 (aged 79)
Birth place:
Dewittville, NY
1878 — 1944 (aged 65)
Birth place:
Ohio
See all burial records

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FAQ

When was Alfred B Slaybaugh born?

Alfred Slaybaugh was born on November 26, 1922

Where was Alfred B Slaybaugh born?

Alfred Slaybaugh was born in Ashtabula, OH

When did is Alfred B Slaybaugh pass away?

Alfred Slaybaugh passed away in June 12, 2005

Where is Alfred B Slaybaugh buried?

Alfred Slaybaugh is interred in Ashtabula, OH

At what age did Alfred B Slaybaugh pass away?

Alfred Slaybaugh passed away at the age of 82

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